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A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car. The cars hook up and move off down the track together. How fast are they going? ( also how do I do it )

Respuesta :

boffeemadrid

Answer:

[tex]0.5ms^{-1}[/tex]

Step-by-step explanation:

Let v be the speed after the collision of both the cars.

Now, momentum is given by: mass × velocity, then by equating the total momentum before and after the collision of the two cars, we get

[tex]500{\times}0.8+300{\times}0=(500+300)v[/tex]

⇒[tex]400+0=800v[/tex]

⇒[tex]400=800v[/tex]

⇒[tex]v=0.5ms^{-1}[/tex]

Thus, they are moving at the velocity of [tex]0.5ms^{-1}[/tex]

isyllus

Answer:

0.5 m/s

Step-by-step explanation:

A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car.

Initial velocity of train, [tex]v_T=0.8\ m/s[/tex]

Initial velocity of car, [tex]v_C=0\ m/s[/tex]

Mass of train, [tex]m_T=500\ g[/tex]

Mass of car, [tex]m_C=300\ g[/tex]

The cars hook up and move off down the track together.

Let the final velocity of car and train, [tex]v_T=v_C=v[/tex]

Using conservation of momentum,

Momentum before collision = Momentum after collision

[tex]m_T\times v_T+m_C\times v_C=(m_T+m_C)\times v[/tex]

[tex]500\times 0.8+300\times 0=(500+300)\times v[/tex]

[tex]v=\dfrac{400}{800}[/tex]

[tex]v=0.5\ m/s[/tex]

Hence, After collision they will going with 0.5 m/s

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