Answer:
2x + 3
(g/f)(x) = ------------
x^2 - 9
------------------------------------------------------
all real numbers other than +3 and -3
Step-by-step explanation:
If: f(x) =x^2-9 and g(x) =2x+3,
then the quotient function (g/f)(x) is as follows:
2x + 3
(g/f)(x) = ------------
x^2 - 9
The denominator here determines the domain: Because we cannot divide by zero, we intentionally set the denominator x^2 - 9 = to zero and solve for x: The solutions are +3 and -3.
The domain consists of "all real numbers other than +3 and -3," or:
(-infinity, -3) ∪ (-3, 3), ∪ (3, infinity)
