A 60-gram sample of radioactive isotope is measured after two half-lives have passed. What pair of percentages describe the sample after two-half lives? A.) 50% unchanged and 50% stable B.) 25% unchanged and 75% stable C.) 12.5% unchanged and 87.5% stable D.) 75% unchanged and 25% stable

Respuesta :

Answer: B.) 25% unchanged and 75% stable

Explanation:

Now, to calculate the initial amount of radioactive isotope

[tex]a=\frac{a_o}{2^n}[/tex]

where,

a = amount of reactant left after n-half lives = 60 g

[tex]a_o[/tex] = Initial amount of the reactant = ?

n = number of half lives= 2

Putting values in above equation, we get:

[tex]60=\frac{a^0}{2^2}[/tex]

[tex]a_0=240g[/tex]

Thus percentage of sample unchanged=[tex]\frac{60}{240}\times 100\%=25\%[/tex]

The percentage of sample decayed or has become stable=[tex]\frac{180}{240}\times 100\%= 75\%[/tex]

Answer:

B. 25% unchanged and 75% stable

Explanation:

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