Solution:
In This question we have given that
velocity of bus=[tex]13\frac{m}{s}[/tex] towards East
Velocity of Man=[tex]0.7\frac{m}{s}[/tex] Towards East
It means Both are moving in the same direction
Therefore velocity of man in the frame of reference of a stationary observer is given as=velocity of bus+velocity of man
=[tex]13\frac{m}{s}+0.7\frac{m}{s}[/tex]
=[tex]13.7\frac{m}{s}[/tex] towards east
Therefore, Therefore velocity of man in the frame of reference of a stationary observer is [tex]13.7\frac{m}{s}[/tex] Towards east
