Respuesta :
Answer:
45.5 yards.
Step-by-step explanation:
We are given that two players are located at the points A and B in the rectangular field.
It is given that,
Point A is located 50 yards from the west edge and 25 yards from the south edge.
Thus, point A is given by the co-ordinate (50,25).
Also, Point B is located 12 yards from the east edge and 0 yards from the south edge.
So, point B is given by the co-ordinate (12,0).
Now, we need to find the distance between the points (50,25) and (12,0).
'The distance between two points [tex](x_{1},y_{1})[/tex] and [tex](x_{2},y_{2})[/tex] is given by [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]'.
So, the required distance is,
Distance between players = [tex]\sqrt{(12-50)^{2}+(0-25)^{2}}[/tex]
i.e. Distance between players = [tex]\sqrt{(-38)^{2}+(-25)^{2}}[/tex]
i.e. Distance between players = [tex]\sqrt{1444+625}[/tex]
i.e. Distance between players = [tex]\sqrt{2069}[/tex]
i.e. Distance between players = 45.5 yards.
Thus, the distance between the two players located at A and B is 45.5 yards.
