Respuesta :
ANSWER
Yes,
[tex]x > 5[/tex]
is the restriction.
EXPLANATION
The given function is
[tex]f(x) = log(x - 5) + 1[/tex]
This is a logarithmic function that is defined for
[tex]x - 5 > 0[/tex]
The reason is that, the logarithmic functions are not defined for negative values of x and 0.
Therefore the argument must always be positive.
When we solve the above inequality, we get,
[tex]x > 5[/tex]
Therefore the the restrictions is that,
[tex]x > 5[/tex]
This is also the same as the domain of the function.
Yes,
[tex]x > 5[/tex]
is the restriction.
EXPLANATION
The given function is
[tex]f(x) = log(x - 5) + 1[/tex]
This is a logarithmic function that is defined for
[tex]x - 5 > 0[/tex]
The reason is that, the logarithmic functions are not defined for negative values of x and 0.
Therefore the argument must always be positive.
When we solve the above inequality, we get,
[tex]x > 5[/tex]
Therefore the the restrictions is that,
[tex]x > 5[/tex]
This is also the same as the domain of the function.
Answer:
1) F(x) is not defined for x=5
2) Restriction for domain; x>5
Step-by-step explanation:
Here the given function is F(x) = log(x-5) +1
In this function if we put the value x =5 then F(5) becomes
F(5) = log(5-5) +1
F(5) = log 0 +1 = ∞
Which indicates that the function F(x) is not defined at x=5.
Now we know that for any negative value of x, logx is not defined Therefore F(x) is defined only for the value of (x-5)>0
Or there is a restriction on domain that x>5.
So there is one restriction on its domain for the given function.