two gears are connected and are rotating simultaneously. The smaller gear has a radius of 3 inches, and the larger gear has a radius of 7 inches.


Part 1: What is the angle measure, in degrees and rounded to the nearest tenth, through which the larger gear has rotated when the smaller gear has made one complete rotation?

Part 2: How many rotations will the smaller gear make during one complete rotation of the larger gear?

two gears are connected and are rotating simultaneously The smaller gear has a radius of 3 inches and the larger gear has a radius of 7 inches Part 1 What is t class=

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Answer:

Part 1: Angle = 154.3°

Part 2: About 2.33 Rotations


Step-by-step explanation:


Part 1:

The arc length of a circle is given by the formula  [tex]s=r\theta[/tex]

Where

  • s is the arc length
  • r is the radius of the circle
  • [tex]\theta[/tex] is the angle

**The angle are in radians and we will use radian**

When smaller gear has made 1 complete rotations ([tex]2\pi[/tex] radians), the arc length traveled is [tex]s=r\theta\\s=(3)(2\pi)\\s=6\pi[/tex]


Now, what angle is swept by the larger circle when it travels [tex]6\pi[/tex]? Put in [tex]s=6\pi[/tex] and r is 7 to find [tex]\theta[/tex]:

[tex]s=r\theta\\6\pi=(7)\theta\\\theta= \frac{6\pi}{7}[/tex]

** Since [tex]\pi[/tex] radians is 180°, we plug in 180 into [tex]\pi[/tex] and find the degree measure:

[tex]\frac{6\pi}{7}=\frac{6*180}{7}=154.3[/tex]

Angle = 154.3°


Part 2:

In one complete rotation of the larger gear, it travels a distance of:

[tex]s=r\theta\\s=(7)(2\pi)\\s=14\pi[/tex]

We know that the smaller circle makes 1 rotation and travels [tex]s=r\theta=(3)(2\pi)=6\pi[/tex], so in [tex]14\pi[/tex] distance, it makes:

Rotations = [tex]\frac{14\pi}{6\pi}=\frac{14}{6}=2.33[/tex]

About 2.33 Rotations