Answer:
The percentage of the students scored higher than 89% is 15.87%
Step-by-step explanation:
we are given
The average test scores for a particular test in algebra was 84
so, mean is 84
[tex]\mu=84[/tex]
a standard deviation of 5
so,
[tex]\sigma=5[/tex]
we have
x=89
now, we can use z-score formula
[tex]z=\frac{x-\mu}{\sigma}[/tex]
now, we can plug values
[tex]z=\frac{89-84}{5}[/tex]
[tex]z=1[/tex]
now, we can use calculator
and we get
[tex]p(z>1)=0.1587[/tex]
So,
The percentage of the students scored higher than 89% is 15.87%
