What are the first six terms of the sequence a1=0,an=an-1-8

Answer:
Step-by-step explanation:
[tex]a_1=0\\\\a_n=a_{n-1}-8\\\\\text{Put n = 2, n = 3, n = 4, n = 5 and n = 6 to the expression:}\\\\a_2=a_1-8\to a_2=0-8=-8\\\\a_3=a_2-8\to a_3=-8-8=-16\\\\a_4=a_3-8\to a_4=-16-8=-24\\\\a_5=a_4-8\to a_5=-24-8=-32\\\\a_6=a_5-8\to a_6=-32-8=-40[/tex]
Answer:
a1 =0
a2 = -8
a3 = -16
a4 = -24
a5 = -32
a6 = -40
Step-by-step explanation:
a1 =0
an = an-1 -8
We subtract 8 each time
a1 =0
a2 = 0-8 = -8
a3 = -8 -8 = -16
a4 = -16 -8 = -24
a5 = -24-8 = -32
a6 = -32-8 = -40