Answer:
a(a+3) are the terms which can be cancelled.
Step-by-step explanation:
In this question if we factorize both the expressions then we can get the common factors which can be cancelled.
So first we factorize a²+3a = a( a+3 )
Now the second expression [tex]a^{3}-2a^{2}-15a[/tex]
⇒[tex]a(a^{2}-2a-15)[/tex]
⇒[tex]a(a^{2}-5a+3a-15)[/tex]
⇒[tex]a\left \{ a(a-5))+3(a-5)) \right \}[/tex]
⇒[tex]a(a+3)(a-5)[/tex]
Now it is clear to us that factors a(a+3) are the common factors that can be cancelled.
Answer:
a and (a+3)
Step-by-step explanation:
We have the following expression and we will simplify it and see which terms can be cancelled out:
[tex] \frac {a^2 + 3a} { a^3 - 2a^2 - 15a } [/tex]
Now factoring both the numerator and the denominator to get the like terms which can then be cancelled out.
[tex] \frac {a^2 + 3a} {a^3 - 2a^2 - 15a } = \frac { a ( a + 3 ) }{a ( a - 5 )( a + 3 )}[/tex]
[tex]a[/tex] and [tex](a+3)[/tex] are the common terms so they are cancelled and we are left with [tex]\frac{1}{(a-5)}[/tex].
