Answer : The number of moles of [tex]CsXeF_7[/tex] produced from the reaction is, 14 moles
Explanation :
The given balanced reaction is,
[tex]CsF(s)+XeF_6(s)\rightarrow CsXeF_7(s)[/tex]
By the stoichiometry, 1 mole of cesium fluoride react with the 1 mole of xenon hexafluoride to give 1 mole of cesium xenon heptafluoride.
That means the mole ratio of [tex]CsF:XeF_6:CsXeF_7=1:1:1[/tex]
As 14 moles of cesium fluoride react with the 14 moles of xenon hexafluoride to give 14 moles of cesium xenon heptafluoride.
Hence, the number of moles of [tex]CsXeF_7[/tex] produced from the reaction is, 14 moles
