Answer:
0.38
Step-by-step explanation:
Let the even that a person has a dog be A. The probability is given 16% this implies:
P(A) = 0.16 ..... (1)
Let the event that a person has a cat denote by B. The probability of B is given to be 32% this implies....
P(B) = 0.32 ..... (2)
Then the event that a person has a dog and a cat will be denoted by A∩B. The probability of A∩B is given to be 10%: This implies:
P(A∩B= = 0.12 .......(3)
The event that someone owns a cat and a dog will denoted by the event A∪B. It is observed that A and B are not disjoint. This implies that the probability of this event is depicted as:
P(A∪B) = P (A) + P(B) - P(A∩B)
Substitute (1) , (2) and (3), in the above, we get:
P(A∪B) = 0.16 + 0.32 - 0.10 = 0.38
