A circle with area 9Pie has a sector with a central angle of 60°

Answer is 3/2pie
Area=
[tex]\pi \times r {?}^{2} [/tex]
So area is 9 pie
Sector=
[tex] \frac{\pi \times r ^{2} \times 60 {}^{0} }{360 {}^{0} } [/tex]
So you just replace area with 9pie
[tex] \frac{9\pi \times 60 {}^{0} }{360 {}^{0} } [/tex]
And then you just simplify
[tex] \frac{9\pi}{6} [/tex]
Thus you get= 3/2pie