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The diagram shows a rectangle , ABCD . If the area of ABCD is 30cm
[tex]30 {}^{2} [/tex]
, calculate the values of x and y​

The diagram shows a rectangle ABCD If the area of ABCD is 30cmtex30 2 tex calculate the values of x and y class=

Respuesta :

First, let's find the clues that the question provides.

From the diagram, we know that the length of sides AB & CD are equal, that is, AB=CD since this is the property of a rectangle where they are parallel sides of the same length. Therefore:

[tex]2 + x = 6 \\ x = 6 - 2 \\ x = 4[/tex]

Next, the question also tells you the area of the rectangle. The area of a rectangle is given by the formula, Area = Length x Heights. So, we can say that multiplying the side AB, which is the length, with side AD gives you the area:

[tex](y + 2)(6) = 30 \\ y + 2 = \frac{30}{6} \\ y = \frac{30}{6} - 2 \\ y = 3[/tex]

Hope this helps!