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The graph of a quadratic function f(x) intersects the x-axis At -3 and 5. Create a function that would produce these results.

Respuesta :

Ashraf82

Answer:

f(x) = x² - 2x - 15

Step-by-step explanation:

∵ The function intersect x-axis at -3 and 5

∴ f(x) = 0 at x = -3 , 5

∵ The form of the quadratic equation is ⇒ ax² + -b/a x + c/a = 0

                                                                       ax² - b/a x + c/a = 0

Where the sum of its roots is b/a and their multiplication is c/a

∵ a = 1

∵ -3 , 5 are the roots of the quadratic equation

∴ b = -3 + 5 = 2

∴ c = -3 × 5 = -15

∴ f(x) = x² - 2x - 15

raphealnwobi

The quadratic function f(x) = x² - 2x - 15 intersects the x-axis at -3 and 5

What is a polynomial?

A polynomial is an expression that involves only the operations of addition, subtraction, multiplication of variables.

A quadratic function is a polynomial of degree two.

Given that the quadratic function f(x) intersects the x-axis At -3 and 5. Hence:

x = -3; and x = 5

x + 3 = 0; and x - 5 = 0

f(x) = (x + 3)(x - 5)

f(x) = x² - 2x - 15

The quadratic function f(x) = x² - 2x - 15 intersects the x-axis at -3 and 5

Find out more on polynomial at: https://brainly.com/question/2833285

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