Respuesta :

[tex]\bf A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-6}{4-(-2)}\implies \cfrac{5-6}{4+2}\implies -\cfrac{1}{6}[/tex]

znk

Answer:

Slope = -⅙

Step-by-step explanation:

The line passes through (-2, 6) and (4,5).

The point-slope formula for a straight line is

y₂ - y₁ = m(x₂ - x₁)

Insert the points  

5 – 6 = m[4 – (-2)]

     -1 = m × 6

Divide each side by 6

m = -⅙

The slope of the line is -⅙.

The Figure below shows the graph of your line passing through (-2, 6) and (4, 5)with a slope of -⅙.

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