The solution of a weak acid and its salt with strong base will make a buffer solution
Buffer solution is the solution which resists change in pH on addition of small amount of acid or base
the pH of buffer solution can be calculated using Hendersen Hassalbalch's equation
the equation is
[tex]pH=pKa+log\frac{[salt]}{[acid]}[/tex]
given
pKa = 4.7
[salt] = moles of salt / total volume
moles of salt = molarity X volume = 1 X 10 = 10mmol
[salt]= 10/60 = 0.167
[acid] = moles of acid / total volume
moles of acid = molarity X volume = 1 X 50 = 50mmol
[acid]=50/60 = 0.833
pH = 4.7 + log [0.833/00167] = 4.7-0.698 =4
Answer: pH will be 4
