From laws of motion:
[tex]S = ( \frac{v + u}{2} ) \times t[/tex]
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s
Substitute the values, hence:
[tex]S = ( \frac{0 + 36}{2} ) \times 6[/tex]
[tex]S = (18) \times 6 \\ \\ S = 108m[/tex]
But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.
Therefore, the distance between the car and the cows = 160-108
Distance = 52m
