Answer:
[tex]\large\boxed{A=153\ in^2}[/tex]
Step-by-step explanation:
We have the ractangle and the trapezoid.
The formula of an area of a rectangle:
[tex]A_{rectangle}=lw[/tex]
l - length
w - width
The formula of an area of a trapezoid:
[tex]A_{trapezoid}=\dfrac{b_1+b_2}{2}\cdot h[/tex]
b₁, b₂ - bases
h - height
RECTANGLE:
l = 3 in, w = 16 in
[tex]A_{rectangle}=(3)(16)=48\ in^2[/tex]
TRAPEZOID:
b₁ = 16 in, b₂ = 5 in, h = 10 in
[tex]A_{trapezoid}=\dfrac{16+5}{2}\cdot10=\dfrac{21}{1}\cdot5=105\ in^2[/tex]
The area of the figure:
[tex]A=A_{rectangle}+A_{trapezoid}[/tex]
Substitute:
[tex]A=48+105=153\ in^2[/tex]
