The average time that it takes for the car to travel the first 0.25m is 2.23 s
The average time that it takes for the car to travel the first 0.25 m is given by:
[tex]t=\frac{2.24 s+2.21 s+2.23 s}{3}=2.227 s \sim 2.23 s[/tex]
The average time to travel just between 0.25 m and 0.50 m is 0.90 s
First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:
[tex]t_1 = 3.16 s - 2.24 s=0.92 s\\t_2 = 3.08 s- 2.21 s=0.87 s\\t_3 =3.15 s- 2.23 s=0.92 s[/tex]
Then, the average time can be calculated as
[tex]t=\frac{0.92 s+0.87 s+0.92 s}{3}=0.90 s[/tex]
Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s
The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):
[tex]v=\frac{d}{t}=\frac{0.25 m}{0.90 s}=0.28 m/s[/tex]
