Respuesta :
a) KE=0.5*mv^2==0.5*145*25^2=45312.5 J
b) PE=mgh=145*9.8*3.5=4973.5 J
c) ME=KE+PE=m(0.5v^2+gh)=62524 J
Answer:
(A) 45312.5 J
(B) 5075 J
(C) 62640 J
Explanation:
m = 145 kg
(a) v = 25 m/s
The energy possessed by the body by virtue of its motion is called kinetic energy. The formula for kinetic energy is given by
[tex]K = \frac{1}{2}mv^{2}[/tex]
[tex]K = \frac{1}{2}\times 145\times 25^{2}[/tex]
K = 45312.5 Joule
(b) h = 3.5 m
The energy possessed by the body by virtue of its position is called potential energy.
P = mgh
P = 145 x 10 x 3.5
P = 5075 Joule
(c) v = 28 m/s, h = 4 m
The sum of the kinetic energy and potential energy is called mechanical energy.
M.E. = 1/2 mv^2 + mgh
M.E. = 0.5 x 145 x 28 x 28 + 145 x 10 x 4
M.E. = 56840 + 5800
M.E. = 62640 Joule
