What is the relation between the variables in the equation x^4/y=7?

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carlosego carlosego · Answer 1 · 2019-02-25T16:48:57+01:00

Answer: OPTION C

Step-by-step explanation:

Direct variation, by definition, has the form shown below:

y=kx

Where k is the constant of proportionality.

Therefore, if you solve for y from the equation given in the problem above, you obtain:

[tex]y=\frac{x^{4}}{7}[/tex]

Where k=1/7

Therefore, it is a direct variation where y varies directly as x^4 (The option is C).

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eudora eudora · Answer 2 · 2019-02-25T16:48:58+01:00

Answer:

Option C is the correct option.

Step-by-step explanation:

The given expression is [tex]x^{4}/y = 7[/tex]

Further we simplify the expression as

[tex]y=\frac{1}{7}x^{4}[/tex]

Now if we put the value of x as 1, 2, 3, 4

Then [tex]y = \frac{1}{7}x^{4}[/tex]

For x = 1

y = 1/7×1 = 1/7

For x = 2

[tex]y = \frac{2^{4} }{7} = \frac{1}{7}.16[/tex]

For x = 3

[tex]y=\frac{1}{7}.3^{4}=\frac{81}{7}[/tex]

That means when we increase the value of x value of y gets increased.

Therefore y varies directly as [tex]x^{4}[/tex]

Option C is the correct option.