The x-component of his applied force is 101.77 N.
The y-component of his applied force is 63.59 N.
The normal force acting on the couch is 161.81 N.
How to find the x-component of applied force?
- The x-component of the applied force is the projection of the vector on x-axis.
So, it will be force applied by jack x sin(32)
= 120 x sin(32)
= 101.77 N
How to find the y-component of applied force?
- The y-component of the applied force is the projection of the vector on y-axis.
So, it will be force applied by jack x cos(32)
= 120 x cos(32)
= 63.59 N
How to find the normal force acting on the couch?
- The resultant force will be 0.
- Therefore F + (y-component of applied force) - W = 0
- Here F is normal force acting on the couch and W is force due to gravitation which is mg.
So, F + (y-component of applied force) - W = 0
∴ F = W - (y-component of applied force)
∴ F = mg - (y-component of applied force)
∴ F = 23(9.8) - 63.59
∴ F = 161.81 N
Hence, The x-component of his applied force is 101.77 N.
The y-component of his applied force is 63.59 N.
The normal force acting on the couch is 161.81 N.
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