Answer:
The two possible solutions are -3 or 4.
Step-by-step explanation:
[tex]x^{2}=x+12\\x^{2} -x-12=0\\x^{2}-+3x-4x-12=0\\x(x+3)-4(x+3)=0\\(x-4)(x+3)=0\\x=-4/x=3[/tex]
Answer:
The correct answer is option C.
Step-by-step explanation:
Let the number be x.
The square of a number exceeds that number by 12 .Mathematically can be written as:
[tex]x^2-x=12[/tex]
[tex]x^2-x-12=0[/tex]
Using middle term splitting to factorize the expression:
[tex]x^2-4x+3x-12=0[/tex]
[tex]x(x-4)+(3)(x-4)=0[/tex]
[tex](x+3)(x-4)=0[/tex]
The two possible solutions are :
1) (x+3)=0
x = -3
2) (x-4)=0
x = 4
