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Janae and Jerome each have m marbles. Gwen has 4(m + 2) marbles. John has 8m + 4 marbles. If John has more marbles than Janae, Jerome, and Gwen combined, how many marbles might Janae and Jerome each have? Select each possible answer.
A.
Janae and Jerome each have 1 marble.
B.


Janae and Jerome each have 2 marbles.
C.


Janae and Jerome each have 3 marbles.
D.


Janae and Jerome each have 4 marbles.
E.


Janae and Jerome each have 5 marbles.​

Respuesta :

frika

Answer:

C, D, E

Step-by-step explanation:

The numbers of marbles are:

  • Janae - m;
  • Jerome - m;
  • Gwen - 4(m+2);
  • John - 8m+4.

Janae, Jerome, and Gwen combined have

m + m + 4(m+2) = m + m +4m + 8 =6m + 8 marbles.

If John has more marbles than Janae, Jerome, and Gwen combined, then

[tex]8m+4>6m+8,\\ \\8m-6m>8-4,\\ \\2m>4,\\ \\m>2.[/tex]

So, possible answers are

  • Janae and Jerome each have 3 marbles;
  • Janae and Jerome each have 4 marbles;
  • Janae and Jerome each have 5 marbles.

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