Answer:
Amplitude 2
Period: [tex]\frac{2\pi}{3}[/tex]
Phase shift: [tex]\frac{\pi}{4}[/tex] units to the right
Step-by-step explanation:
The given function is [tex]y=2\sin(3(x-\frac{\pi}{4}))[/tex]
This function is of the form [tex]y=A\sin(Bx+C)[/tex]
where [tex]A=|2|=2[/tex] is the amplitude.
The period is [tex]\frac{2\pi}{B}= \frac{2\pi}{3}[/tex]
This function is shifted [tex]\frac{\pi}{4}[/tex] units to the right
