Answer:
The equation would be -x + 4y = -8
Step-by-step explanation:
To find the standard form of the line, solve for the constant.
y - 1 = 1/4(x - 12)
y - 1 = 1/4x - 3
-1/4x + y - 1 = -3
-1/4x + y = -2
-x + 4y = -8
Answer: The standard equation of this line is x-4y=8.
Step-by-step explanation:
Since we have given that
Two coordinates are as follows:
(-4,-3) and (12,1)
So, slope would be
[tex]\dfrac{y_2-y_1}{x_2-x_1}\\\\\\=\dfrac{1-(-3)}{12-(-4)}\\\\\\=\dfrac{1+3}{12+4}\\\\\\=\dfrac{4}{16}\\\\\\=\dfrac{1}{4}[/tex]
So, the standard form of equation of this line is given by
[tex]y-y_1=\dfrac{1}{4}(x-x_1)\\\\y-(-3)=\dfrac{1}{4}(x-(-4)\\\\y+3=\dfrac{1}{4}(x+4)\\\\4(y+3)=x+4\\\\4y+12=x+4\\\\4y=x+4-12\\\\4y=x-8\\\\-x+4y=-8\\\\x-4y=8[/tex]
Hence, the standard equation of this line is x-4y=8.
