robert7248
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a. How does increasing the voltage of a power supply in an electromagnet affect the strength of the magnetic field?

b. Write two or three sentences to identify the energy conversion that takes place in an electric generator and to describe how electromagnertism is involved.

c. What does a step-up transformer change in an alternating current?

d. What si the magnetic force on a particle that has 0.000600 C of charge and is moving at [tex]2.8 x 10^{5}[/tex] m/s to the right through of magnetic field that is 4.21 T and pointing towards you? Specify both magnitude and direction in your answer.

Respuesta :

PART A)

If we increase the voltage supply in an electromagnet then it will increase the current that is flowing in it

So here due to increase in current there will be increase in the magnetic field due to that electromagnet

PART B)

Here in electric generator the current is produced by rotating a coil between two strong magnets.

So here mechanical energy of rotation of coil is converted into electromagnetic energy.

PART C)

Step up transformer convert the lower voltage input into higher voltage output

here number of turns of coil in output side or secondary number of coils is more than the number of coils in primary side or input side

PART D)

Force on a moving charge is given by

[tex]F = q(\vec v \times \vec B)[/tex]

here we know that

q = 0.000600 C

[tex]v = 2.8 \times 10^5 m/s[/tex]

B = 4.21 T

now from above equation we have

[tex]F = 0.0006(2.8\times 10^5)(4.21)[/tex]

[tex]F = 707.3 N[/tex]

direction of force is given by right hand thumb rule

using that rule we got force downwards

a) The electromagnetic field will become stronger. More current - more field!

b) Mechanical energy helps to move the generator's shaft. Then electromagnetic energy creates a magnetic field that crosses generator's windings with high frequency. According to Faraday's law change in magnetic flux causes voltage.

c) On the secondary side it increases voltage, decreases current, power remains the same relatively to the primary side.

d) F=qvB=0.0006*2.8*10^5*4.21=707.28 N. The force will look down.

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