Answer:
Option D. [tex]y=28,000(0.86)^{t}[/tex]
Step-by-step explanation:
we know that
The formula to calculate the depreciated value is equal to
[tex]y=P(1-r)^{x}[/tex]
where
y is the depreciated value
P is the original value
r is the rate of depreciation in decimal
x is Number of Time Periods
in this problem we have
[tex]P=\$28,000\\r=14\%=0.14\\x=t\ years[/tex]
substitute
[tex]y=28,000(1-0.14)^{t}[/tex]
[tex]y=28,000(0.86)^{t}[/tex]
