Respuesta :
1. First calculate the total molar mass of the entire compound.
Mg = 3 x 24.31 = 72.93 g/mol
P = 2 x 30.97 = 61.94 g/mol
O = 8 x 16.00 = 128.00 g/mol
* Add them up;
72.93 + 61.94 + 128.00 = 262.87 g/mol
2. Take the individual masses of each element that you calculated, divide them by the total mass (262.87 g/mol) and then multiply by 100.
Mg = 72.93/262.87 = 0.2774 x 100 = 27.74%
P = 61.94/262.87 = 0.2356 x 100 = 23.56%
O = 128.00/262.87 = .4870 x 100 = 48.70%
3. All of the percentages should add up to equal 100%.
* Hope this helps
1. Firstly we have to calculate the total molar mass of the entire compound.
- Then Mg = 3 x 24.31 = 72.93 g/mol
- Then P = 2 x 30.97 = 61.94 g/mol
- After that O = 8 x 16.00 = 128.00 g/mol
- Then Add them up;
- Also that when 72.93 + 61.94 + 128.00 = 262.87 g/mol
2. Now we have to Take the individual masses of each element that you calculated, then divide them by the total mass (262.87 g/mol), and also then multiply by 100.
- After that Mg = 72.93/262.87 = 0.2774 x 100 = 27.74%
- Then P = 61.94/262.87 = 0.2356 x 100 = 23.56%
- Then O = 128.00/262.87 = .4870 x 100 = 48.70%
3. Thus All of the percentages should add up to equal 100%.
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