Respuesta :

carlosego

Answer: second option

Step-by-step explanation:

The standard form of a quadratic equation is:

[tex]ax^2+bx+c=0[/tex]

Then, to write the quadratic equation given in the problem in standard form, you must substract 1 from both sides of the equation. Then you have:

[tex]2x^2+5x-1=0[/tex]

Given the quadratic equation above, to find the value of [tex]b^2-4ac[/tex]  you must substitute:

a=2; b=5 and c=-1 into [tex]b^2-4ac[/tex]

Thenrefore, you obtain the following result:

[tex]5^2-4(2)(-1)=33[/tex]

kudzordzifrancis

Answer:

[tex]33[/tex]

Step-by-step explanation:

The given quadratic equation is

[tex]1=2x^2+5x[/tex]

We want to rewrite this equation in the form;

[tex]ax^2+bx+c=0[/tex]

We add [tex]-1[/tex] to both sides of the equation to obtain;

[tex]0=2x^2+5x-1[/tex]

This is the same as

[tex]2x^2+5x-1=0[/tex]

This implies that;

[tex]a=2,b=5,c=-1[/tex]

We substitute these values into the expression [tex]b^2-4ac[/tex]

[tex]\Rightarrow 5^{2}-4(2)(-1)[/tex]

[tex]=25+8[/tex]

[tex]=33[/tex]

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