Respuesta :
acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.
so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base
(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.
Answer: a) [tex]C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)[/tex]
bronsted- lowry acid : [tex]H_2O[/tex]
conjugate base : [tex]OH^-[/tex]
bronsted- lowry base : [tex]C_5H_5N[/tex]
conjugate acid : [tex]C_5H_5NH^+[/tex]
b) [tex]HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)[/tex]
bronsted-lowry acid : [tex]HNO_3[/tex]
conjugate base : [tex]NO_3^-[/tex]
bronsted- lowry base : [tex]H_2O[/tex]
conjugate acid : [tex]H_3O^+[/tex]
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equation:
a) [tex]C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)[/tex]
Here, [tex]H_2O[/tex] is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms [tex]OH^-[/tex] which is a conjugate base.
And, [tex]C_5H_5N[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]C_5H_5NH^+[/tex] which is a conjugate acid.
b) [tex]HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)[/tex]
Here, [tex]HNO_3[/tex] is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms [tex]NO_3^-[/tex] which is a conjugate base.
And, [tex]H_2O[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]H_3O^+[/tex] which is a conjugate acid.
