Well , its a easy problem
By ohms law,
we have V= IR
Where V is the voltage applied across the wire and R is the resistance and I is the current
=> R = V/I
=> R = 12/0.3 = 40 ohm
The resistance of the copper wire will be 400 ohms. Resistance is found as the ratio of the voltage and electric current.
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The given data in the problem is;
V is the voltage= 12 V
I is the current = 0.30A
R is the resistance
The resistance of the circuit from the Ohm's law is found as;
[tex]\rm V= IR \\\\ R = \frac{V}{I} \\\\\ R = \frac{12}{0.30} \\\\\ R =400 \ ohm[/tex]
Hence, the resistance of the copper wire will be 400 ohms.
To learn more about the resistance, refer to the link;
https://brainly.com/question/20708652
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