Answer:
K'= (-2, 4)
Step-by-step explanation:
First we are going to rotate our point 270° counterclockwise.
The rule for a 270° counterclockwise rotation is [tex](x,y)-->(y,-x)[/tex], which means that we just need to interchange the coordinates of the point and change the sign of the x-coordinate:
[tex](x,y)-->(y,-x)[/tex]
[tex](-7,-2)-->(-2,-7)[/tex]
[tex](-7,-2)-->(-2,-(-7))[/tex]
[tex](-7,-2)-->(-2,7)[/tex]
Now, to shift the point 3 units down, we just need to subtract 3 units from the new y-coordinate of our resulting point form the previous procedure:
[tex](x,y)-->(x,y-3)[/tex]
[tex](-2,7)-->(-2,7-3)[/tex]
[tex](-2,7)-->(-2,4)[/tex]
We can conclude that the coordinates of K' are (-2, 4)
