Respuesta :

Ben

[tex]\huge\text{$x=\boxed{\frac{1}{5}}$}[/tex]

Hey there! To solve this problem, we need to isolate [tex]x[/tex] on one side of the equation.

[tex]\begin{aligned}5(3x+4)&=23\\5\cdot3x+5\cdot4&=23&&\smash{\Big|}&&\text{Distribute the $5$.}\\15x+20&=23&&\smash{\Big|}&&\text{Multiply.}\\15x&=3&&\smash{\Big|}&&\text{Subtract $20$ from both sides.}\\x&=\frac{3}{15}&&\smash{\Big|}&&\text{Divide both sides by $15$.}\\x&=\boxed{\frac{1}{5}}&&\smash{\Big|}&&\text{Divide the numerator and denominator by $3$.}\end{aligned}[/tex]

alinakincsem

Answer:

[tex] x = \frac { 1 } { 5 } [/tex]

Step-by-step explanation:

We are given the following equation and we are to find the value of x by making it the subject of the equation:

[tex] 5 ( 3 x + 4 ) = 23 [/tex]

We will start by opening the brackets and expanding the term by multiplying 5 with the terms inside the brackets to get:

[tex] 15 x + 20 = 23 [/tex]

[tex] 15 x = 23 - 20 [/tex]

[tex] 15 x = 3 [/tex]

[tex] x = \frac { 3 }  { 15 } [/tex]

[tex] x = \frac { 1 } { 5 } [/tex]

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