3/4(8x-4)=7x+2 This is a linear equation please help!

Simplify the left hand side by multiplying the terms in the parenthesis by 3/4, i.e. divide them by 4 and multiply them by 3:
[tex]\dfrac{3}{4}(8x-4)=7x+2 \iff 3(2x-1)=7x+2 \iff 6x-3 = 7x+2 [/tex]
Subtract 6x from both sides:
[tex]-3=x+2[/tex]
Subtract 2 to both sides:
[tex]x=-5[/tex]