Answer:
0.45 J/gC
Explanation:
The heat absorbed by the sample of iron is given by:
[tex]Q=mC_s (T_f-T_i)[/tex]
where:
Q = 1004 J is the heat absorbed
m = 111.6 g is the mass of the sample
Cs is the specific heat capacity of iron
T_f = 20 C is the final temperature of the sample
T_i = 0 C is the initial temperature
Solving the equation for Cs, we find
[tex]C_s = \frac{Q}{m(T_f-T_i)}=\frac{1004 J}{(111.6 g)(20 C-0 C)}=0.45 J/gC[/tex]
