Respuesta :

damisolatolu

Potential energy=mass*acceleration due to gravity*height

= 8 000 000 * 9.8 * 50

= 3.92 * 10^9

onyebuchinnaji

The change in the potential energy of the Niagara falls is - 3.92 x 10⁹ J.

The given parameters;

  • mass of the water, m = 8 x 10⁶ kg
  • height of the water fall, h = 50 m.

The change in the potential energy of the waterfall is calculated as follows;

ΔP.E = mgh₂ - mgh₁

ΔP.E = mg(h₂ - h₁)

where;

  • h₂ is the final height of the waterfall
  • h₁ is the initial height of the waterfall

ΔP.E = 8 x 10⁶ x 9.8(0 - 50)

ΔP.E = - 3.92 x 10⁹ J

Thus, the change in the potential energy of the Niagara falls is - 3.92 x 10⁹ J.

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