Answer: [tex]x_1=2\\\\x_2=-\frac{1}{2}[/tex]
Step-by-step explanation:
To find the zeros of the quadratic equation given in the exercise, you need to apply the proccedure shown below:
- You must rewrite it as following:
[tex]6x^2-9x-6=0[/tex]
-You can apply the Quadratic formula, which is shown below:
[tex]x=\frac{-b\±\sqrt{b^2-4c}}{2a}[/tex]
In this case:
[tex]a=6\\b=-9\\c=-6[/tex]
- Therefore, when you substitute values, you obtain:
[tex]x=\frac{-(-9)\±\sqrt{(-9)^2-4(6)(-6)}}{2(6)}[/tex]
[tex]x_1=2\\\\x_2=-\frac{1}{2}[/tex]
