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Identify the vertex and the y-intercept of the graph of the function.

y = –0.25(x – 4)^2 2 – 2


vertex, (2, –4); y-intercept, –6


vertex, (–4, 0); y-intercept, –6


vertex, (4, –2); y-intercept, –6


vertex, (–2, 4); y-intercept, –6

Respuesta :

MrsStrong

Answer:

vertex, (4, –2); y-intercept, –6

Step-by-step explanation:

The equation is written in vertex form [tex]y = a(x-h)^2 + k[/tex] where the vertex is (h,k).

The vertex here is (4, -2). This means the solution is vertex, (4, –2); y-intercept, –6.

botellok

Answer:

vertex, (4, –2); y-intercept, –6.

Step-by-step explanation:

[tex]y=-0.25(x-4)^{2}-2[/tex]

[tex]y=-0.25(x^{2}-8x+16)-2[/tex]

[tex]y=-0.25x^{2}+2x-4-2[/tex]

[tex]y=-0.25x^{2}+2x-6[/tex]

the vertex is [tex](\frac{-b}{2a},y(\frac{-b}{2a}) )[/tex] where a=-0.25 and b=2. So,

[tex]\frac{-b}{2a}= \frac{-2}{-0.5}=4[/tex]

[tex]y(\frac{-b}{2a})=-0.25(4)^{2}+2(4)-6= -4+8-6=-2 [/tex]

Then, the vertex is (4,-2) and the intercept is y(0)= -0.25(0)+2(0)-6 = -6. So, the answer is the third option.

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