What is the perimeter of kite OBDE?
12 units
22 units
38 units
58 units

Answer:
38 units
Step-by-step explanation:
Triangle ABC is a right triangle. To find the missing side, AB (which is the hypotenuse), we use the Pythagorean theorem:
a²+b² = c²
10²+24² = c²
100+576 = c²
676 = c²
Take the square root of both sides:
√(676) = √(c²)
26 = c
AB is a diameter; this means the radius is 26/2 = 13. This means that OB = 13 and OE = 13.
BD and DE are congruent; this means that BD = 6.
This makes the perimeter
13+13+6+6 = 38 units.
The perimeter of kite OBDE is 38 units.
Pythagoras theorem states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides.
Perimeter is the distance around the edge of a shape.
A kite is a quadrilateral that has 2 pairs of equal-length sides and these sides are adjacent to each other.
According to the given question.
We have a circle with center o and diameter AB.
Triangle ABC is a right triangle.
To find the missing side, AB (which is the hypotenuse), we use the Pythagoras theorem.
So,
[tex](AB)^{2} = (10)^{2} +(24)^{2}[/tex]
[tex]\implies (AB)^{2} = 100+ 576\\\implies (AB)^{2} = 676\\\implies AB = \sqrt{676} \\\implies AB = 26[/tex]
Since, AB is the diameter of the circle. Therefore,
[tex]OB = \frac{AB}{2} \\\implies OB = \frac{26}{2} = 13[/tex]
Also, OBDE is a kite and we know that the adjacent sides of a kite are congruent.
[tex]\implies OB = BD = 13 \\\And,\ OE = ED = 6[/tex]
Therefore,
the perimeter of kite OBDE
= Length of sides (OB + BD + DE + EO )
= 13 + 13 + 6 + 6
= 26 + 12
= 38 units.
Hence, the perimeter of kite OBDE is 38 units.
Find out more information about perimeter, kite and Pythagoras theorem here:
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