If an ideal monatomic gas undergoes an adiabatic expansion, in which the volume increases by a factor of 4.0, by what factor does the pressure change? a) 2.1 b) 1.7 c) 0.52 d) 0.25 e) 0.099

Respuesta :

Answer:

e) 0.099

Explanation:

For an adiabatic transformation, we have:

[tex]PV^{\gamma}=const.[/tex]

where

P is the gas pressure

V is the volume

[tex]\gamma[/tex] is the adiabatic index, which is [tex]\gamma=\frac{5}{3}[/tex] for an ideal monoatomic gas

The previous law can also be rewritten as

[tex]P_1 V_1 ^{\gamma}= P_2 V_2^{\gamma}[/tex]

or

[tex]\frac{P_2}{P_1}=(\frac{V_1}{V_2})^{\gamma}[/tex]

where we know that

[tex]\frac{V_1}{V_2}=\frac{1}{4}[/tex]

because the volume has increased by a factor 4.0. Substituting into the equation, we find by which factor the pressure has changed:

[tex]\frac{P_2}{P_1}=(\frac{1}{4})^{\frac{5}{3}}=0.099[/tex]