Answer:
b. [tex]-1[/tex]
Step-by-step explanation:
The given limit is
[tex]\lim_{x \to 2} (x^3-3x^2+3)[/tex]
This is the limit of a polynomial function so we plug in the value of x directly to obtain;
[tex]\lim_{x \to 2} x^3-3x^2+3=(2)^3-3(2)^2+3[/tex]
Evaluate
[tex]\lim_{x \to 2} x^3-3x^2+3=8-12+3[/tex]
This simplifies to
[tex]\lim_{x \to 2} x^3-3x^2+3=-1[/tex]
The correct choice is B.
