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What is the value of x? Round your answer to the nearest tenth if necessary.




Right triangle whose two legs measure seven and four, and whose hypotenuse is x

What is the value of x Round your answer to the nearest tenth if necessary Right triangle whose two legs measure seven and four and whose hypotenuse is x class=

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ThePokemonExpert151

So to start off:

The equation you will want to use for the hypotenuse is

A (squared) + B (squared) = C (squared)

So you will want to fill in the equation like so:

7(7) + 4(4) = C (squared)

So now that you have your information filled out, put it all together!

49 + 16 = 65

Now don't forget that the 65 is SQUARED!

You will want to use the SQUARE ROOT method to help with that!

So what you will want to do is think of the numbers that are PERFECT SQUARES.

A perfect square consist of

Here is the list of perfect squares 1-10:

1 x 1 = 1

2 x 2 = 4

3 x 3 = 9

4 x 4 = 16

5 x 5 = 25

6 x 6 = 36

7 x 7 = 49

8 x 8 = 64

9 x 9 = 81

So look closely at these perfect squares, Do you see where 65 will lie?

It will lie between 8 and 9.

So you will do the square root now.

√65

The answer will come out as:

8.06225775

You will then round it to the nearest tenths place (one after the decimal)

You will look at the two numbers behind the decimal which is

0.6.

As you know,(If you round the tenths place), if the number in the hundredths is 5 or HIGHER. It will round up the number in the tenths place to 1.

So as we know 6 is higher than 5 so your answer would be:

8.1

I hope this helped! :)

>^.^<

(      )~


Cyrusskywalker

Answer:

8.1

Step-by-step explanation:

The previous answerer is definitly correct. The number rounded to the nearest Hundreths place is 8.06 but since its asking for the Tenths place the answer closest to 8.06 is 8.1. To get this answer, multiply 7 by itself, that equals 49, then multiply 4 by itself, that is 16. Add both of those to get [tex]\sqrt{65}[/tex]. 65 squared is 8.0622577483 which is rounded to 8.1 because it asks you to round it by the Tenths place. Please choose someone to be brailiest. -----Cyrusskywalker

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