Respuesta :

apologiabiology
make equal to 0
minus 12from both sides
x^2+10x+13=0
we can't factor so use quadratic formula

x= [tex] \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} [/tex]
x= [tex] \frac{-10+/- \sqrt{10^{2}-4(1)(13)} }{2(1)} [/tex]
x= [tex] \frac{-10+/- \sqrt{100-52} }{2} [/tex]
x= [tex] \frac{-10+/- \sqrt{48} }{2} [/tex]
x= [tex] \frac{-10+/- 4\sqrt{3} }{2} [/tex]
x= [tex] -5+/- 2\sqrt{3}  [/tex]


x= [tex] -5+ 2\sqrt{3}  [/tex] or [tex] -5- 2\sqrt{3}  [/tex]

aprox
x=-1.5359 or -8.4641





fatimakincsem

Answer: - 1.536  or - 8.464  

Step-by-step explanation:

Step 1: Rearrange the equation, by putting everything on the left hand side of the equation so that the quadratic formula can be applicable to the equation  

x^2-10*x+25-(12)=0  

Step 2: the quadratic formula

                       

           - B  ±  √ B2-4AC

 x =   ————————

                     2A    

Where A= 1

B = 10

C = 13

B2  -  4AC =  100 - 52  

= 48

            10 ± √ 48  

  x  =    —————

                   2

      -   √ 48  

x =(10-√48)/2=5-2√ 3 =  - 1.536  

x =(10+√48)/2=5+2√ 3 = - 8.464  

Are the two solutions