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One of the main components of pearls is calcium carbonate (CaCO3). If pearls are put into an acidic solution, they dissolve: CaCO3(s) + 2HCl(aq) ➡ CaCl2(aq) + H2O(l) + CO2(g). How many moles of CaCO3 can be dissolved in 0.0250 moles of hydrochloric acid?

0.0125 moles

0.0500 moles

2.50 moles

4.50 moles

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CaCO3 + 2HCl --> CaCl2 + H2O + CO2 

Since the molar ratio of calcium carbonate to Hydrochloric acid is 2:1,
The moles of CaCO3: the moles of HCl is 2:1

Therefore, 0.0250 moles of HCl can dissolve 0.0125 moles of CaCO3 (dividing by 2)

I hope this is right :) 

Answer : The correct option is, 0.0125 moles

Explanation : Given,

Moles of HCl = 0.0250 mole

The given balanced chemical reaction is :

[tex]CaCO_3(s)+2HCl(aq)]\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)[/tex]

From the balanced chemical reaction, we conclude that

As, 2 moles of HCl react with 1 mole of [tex]CaCO_3[/tex]

So, 0.0250 moles of HCl react with [tex]\frac{0.0250}{2}=0.0125mole[/tex] of [tex]CaCO_3[/tex]

Therefore, the number of moles of [tex]CaCO_3[/tex] dissolved will be, 0.0125 mole