Answer:
x = 2 and x = -2
Step-by-step explanation:
The easiest way is to guess. We know that you can't have a square root of a negative number. This constrains x between negative infinity to 2. Testing 2 and -2, we see that it satisfy the equation.
The more systematic approach is shown below
[tex]\sqrt{5-2x}-\sqrt{2-x}=1 \\\sqrt{5-2x}-\sqrt{2-x}+\sqrt{2-x}=1+\sqrt{2-x} \\\sqrt{5-2x} = 1+\sqrt{2-x}[/tex]
[tex]5-2x=(1+\sqrt{2-x})^2\\5-2x=1+2\sqrt{2-x}+2-x\\2-x=2\sqrt{2-x}\\1-0.5x=\sqrt{2-x}\\(1-0.5x)^2=2-x\\1-x+0.25x^2=2-x\\0.25x^2-1=0\\0.25x^2 = 1\\x^2 = 4\\x = +/-2[/tex]
x= -2, 2
