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In a competition between players x and y, the first player to win three games in a row or a total of four games wins. how many ways can the competition be played if x wins the first game and y wins the second and third games?

Respuesta :

sqdancefan

Answer:

  7 ways (y wins 4 of them)

Step-by-step explanation:

Possibilities are ...

{x, y, y, y} — y wins

{x, y, y, x, x, x} — x wins

{x, y, y, x, y, y} — y wins

{x, y, y, x, x, y, x} — x wins

{x, y, y, x, x, y, y} — y wins

{x, y, y, x, y, x, x} — x wins

{x, y, y, x, y, x, y} — y wins

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