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find the area of an area of an equilateral triangle (regular 3-gon) with the given measurement 9-inch perimeter. A=sq. in.​

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wolf1728

Answer:

Area = side^2 * sqrt(3) / 4

If 9 inch perimeter then side = 3

Area = 3^3 * sqrt(3) / 4

Area = (9 / 4) * sqrt(3)

Area = 3.897114317 square inches

Step-by-step explanation:

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Answer:

9/4 √ 3

Hope it helps.

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