There are [tex]\dbinom{10}5=\dfrac{10!}{5!(10-5)!}=252[/tex] ways of getting exactly 5 heads in 10 tosses. There are [tex]2^{10}=1024[/tex] possible outcomes. So the probability of getting exactly 5 heads is
[tex]\dfrac{252}{1024}=\dfrac{63}{256}\approx24.61\%[/tex]
The probability of getting exactly 5 “heads” in 10 coin flips is 0.246 or 24.6%.
It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words the probability is the number that shows the happening of the event.
We have coin flipping 10 times.
Number of total outcomes = 2¹⁰ = 1024
Total number of favourable outcomes = C(10, 5) = 252
Probability = 252/1024 = 0.246 or 24.6%
Thus, the probability of getting exactly 5 “heads” in 10 coin flips is 0.246 or 24.6%.
Learn more about the probability here:
brainly.com/question/11234923
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